315225116141 has 4 divisors (see below), whose sum is σ = 339473202012. Its totient is φ = 290977030272.

The previous prime is 315225116137. The next prime is 315225116179. The reversal of 315225116141 is 141611522513.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 141611522513 = 19 ⋅7453238027.

It can be written as a sum of positive squares in 2 ways, for example, as 74777090116 + 240448026025 = 273454^2 + 490355^2 .

It is a cyclic number.

It is not a de Polignac number, because 315225116141 - 2² = 315225116137 is a prime.

It is a super-2 number, since 2×315225116141² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 315225116098 and 315225116107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (315225118141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12124042916 + ... + 12124042941.

It is an arithmetic number, because the mean of its divisors is an integer number (84868300503).

Almost surely, 2^315225116141 is an apocalyptic number.

It is an amenable number.

315225116141 is a deficient number, since it is larger than the sum of its proper divisors (24248085871).

315225116141 is a wasteful number, since it uses less digits than its factorization.

315225116141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24248085870.

The product of its digits is 7200, while the sum is 32.

Adding to 315225116141 its reverse (141611522513), we get a palindrome (456836638654).

The spelling of 315225116141 in words is "three hundred fifteen billion, two hundred twenty-five million, one hundred sixteen thousand, one hundred forty-one".