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315231360455 = 5112521043571
BaseRepresentation
bin1001001011001010100…
…00001101010111000111
31010010200000102022022102
410211211100031113013
520131043212013310
6400452034022315
731526504232134
oct4454520152707
91103600368272
10315231360455
11111763980900
125111641799b
132395959222b
1411385d8d58b
1582ee9748a5
hex496540d5c7

315231360455 has 12 divisors (see below), whose sum is σ = 415792770456. Its totient is φ = 229259170800.

The previous prime is 315231360449. The next prime is 315231360469. The reversal of 315231360455 is 554063132513.

It is not a de Polignac number, because 315231360455 - 224 = 315214583239 is a prime.

It is a super-2 number, since 2×3152313604552 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 260521181 + ... + 260522390.

It is an arithmetic number, because the mean of its divisors is an integer number (34649397538).

Almost surely, 2315231360455 is an apocalyptic number.

315231360455 is a deficient number, since it is larger than the sum of its proper divisors (100561410001).

315231360455 is a wasteful number, since it uses less digits than its factorization.

315231360455 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 521043598 (or 521043587 counting only the distinct ones).

The product of its (nonzero) digits is 162000, while the sum is 38.

Adding to 315231360455 its reverse (554063132513), we get a palindrome (869294492968).

The spelling of 315231360455 in words is "three hundred fifteen billion, two hundred thirty-one million, three hundred sixty thousand, four hundred fifty-five".

Divisors: 1 5 11 55 121 605 521043571 2605217855 5731479281 28657396405 63046272091 315231360455