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315255351323491 is a prime number
BaseRepresentation
bin100011110101110010001101…
…1001110101010101101100011
31112100020010011110212020000021
41013223210123032222231203
5312310120424414322431
63034254150430534311
7123255306331262515
oct10753443316525543
91470203143766007
10315255351323491
11914a505314a847
122b436723367397
13106ba5b526c787
1457bc624713bb5
15266a7ad9deb11
hex11eb91b3aab63

315255351323491 has 2 divisors, whose sum is σ = 315255351323492. Its totient is φ = 315255351323490.

The previous prime is 315255351323431. The next prime is 315255351323557. The reversal of 315255351323491 is 194323153552513.

It is a weak prime.

It is an emirp because it is prime and its reverse (194323153552513) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 315255351323491 - 231 = 315253203839843 is a prime.

It is a super-4 number, since 4×3152553513234914 (a number of 59 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (315255351323431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157627675661745 + 157627675661746.

It is an arithmetic number, because the mean of its divisors is an integer number (157627675661746).

Almost surely, 2315255351323491 is an apocalyptic number.

315255351323491 is a deficient number, since it is larger than the sum of its proper divisors (1).

315255351323491 is an equidigital number, since it uses as much as digits as its factorization.

315255351323491 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7290000, while the sum is 52.

The spelling of 315255351323491 in words is "three hundred fifteen trillion, two hundred fifty-five billion, three hundred fifty-one million, three hundred twenty-three thousand, four hundred ninety-one".