Base | Representation |
---|---|
bin | 1011101111101111… |
… | …1100110100011001 |
3 | 22010202000210022212 |
4 | 2323323330310121 |
5 | 22424140230001 |
6 | 1240512524505 |
7 | 141064345115 |
oct | 27373746431 |
9 | 8122023285 |
10 | 3153055001 |
11 | 13788a9988 |
12 | 73bb50735 |
13 | 3b3312b25 |
14 | 21ca88745 |
15 | 136c287bb |
hex | bbefcd19 |
3153055001 has 2 divisors, whose sum is σ = 3153055002. Its totient is φ = 3153055000.
The previous prime is 3153054977. The next prime is 3153055013. The reversal of 3153055001 is 1005503513.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1806165001 + 1346890000 = 42499^2 + 36700^2 .
It is a cyclic number.
It is not a de Polignac number, because 3153055001 - 210 = 3153053977 is a prime.
It is a super-2 number, since 2×31530550012 = 19883511678662220002, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3153055091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1576527500 + 1576527501.
It is an arithmetic number, because the mean of its divisors is an integer number (1576527501).
Almost surely, 23153055001 is an apocalyptic number.
It is an amenable number.
3153055001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3153055001 is an equidigital number, since it uses as much as digits as its factorization.
3153055001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1125, while the sum is 23.
The square root of 3153055001 is about 56152.0703180212. The cubic root of 3153055001 is about 1466.3709517847.
Adding to 3153055001 its reverse (1005503513), we get a palindrome (4158558514).
The spelling of 3153055001 in words is "three billion, one hundred fifty-three million, fifty-five thousand, one".
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