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3153130053 = 323337135601
BaseRepresentation
bin1011101111110000…
…1111001001000101
322010202011121021120
42323330033021011
522424200130203
61240514304153
7141065106663
oct27374171105
98122147246
103153130053
111378950307
1273bb88059
133b333b038
1421caa7c33
15136c40b53
hexbbf0f245

3153130053 has 16 divisors (see below), whose sum is σ = 4400013696. Its totient is φ = 2004710400.

The previous prime is 3153130049. The next prime is 3153130073. The reversal of 3153130053 is 3500313513.

It is not a de Polignac number, because 3153130053 - 22 = 3153130049 is a prime.

It is a super-2 number, since 2×31531300532 = 19884458262263565618, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3153130073) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44548 + ... + 91053.

It is an arithmetic number, because the mean of its divisors is an integer number (275000856).

Almost surely, 23153130053 is an apocalyptic number.

It is an amenable number.

3153130053 is a deficient number, since it is larger than the sum of its proper divisors (1246883643).

3153130053 is a wasteful number, since it uses less digits than its factorization.

3153130053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 135964.

The product of its (nonzero) digits is 2025, while the sum is 24.

The square root of 3153130053 is about 56152.7386064117. The cubic root of 3153130053 is about 1466.3825863422.

Adding to 3153130053 its reverse (3500313513), we get a palindrome (6653443566).

The spelling of 3153130053 in words is "three billion, one hundred fifty-three million, one hundred thirty thousand, fifty-three".

Divisors: 1 3 23 69 337 1011 7751 23253 135601 406803 3118823 9356469 45697537 137092611 1051043351 3153130053