Base | Representation |
---|---|
bin | 1001001011010110101… |
… | …00101100100010110011 |
3 | 1010010221010001021222022 |
4 | 10211223110230202303 |
5 | 20131300244400201 |
6 | 400510112502055 |
7 | 31532151655442 |
oct | 4455324544263 |
9 | 1103833037868 |
10 | 315333200051 |
11 | 111806409461 |
12 | 5114454a92b |
13 | 239746cb14c |
14 | 113956dcd59 |
15 | 830888e41b |
hex | 496b52c8b3 |
315333200051 has 2 divisors, whose sum is σ = 315333200052. Its totient is φ = 315333200050.
The previous prime is 315333199963. The next prime is 315333200069. The reversal of 315333200051 is 150002333513.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-315333200051 is a prime.
It is not a weakly prime, because it can be changed into another prime (315333200251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157666600025 + 157666600026.
It is an arithmetic number, because the mean of its divisors is an integer number (157666600026).
Almost surely, 2315333200051 is an apocalyptic number.
315333200051 is a deficient number, since it is larger than the sum of its proper divisors (1).
315333200051 is an equidigital number, since it uses as much as digits as its factorization.
315333200051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4050, while the sum is 26.
Adding to 315333200051 its reverse (150002333513), we get a palindrome (465335533564).
The spelling of 315333200051 in words is "three hundred fifteen billion, three hundred thirty-three million, two hundred thousand, fifty-one".
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