Base | Representation |
---|---|
bin | 1110010101110010110000… |
… | …11101011110101100010101 |
3 | 11010122201200201011112111020 |
4 | 13022321120131132230111 |
5 | 13113132423301311013 |
6 | 151023012432431353 |
7 | 6433224006233205 |
oct | 712713035365425 |
9 | 133581621145436 |
10 | 31535134010133 |
11 | a058a80036256 |
12 | 36538786a8559 |
13 | 147999a76a360 |
14 | 7b0446c48405 |
15 | 39a47b875623 |
hex | 1cae5875eb15 |
31535134010133 has 32 divisors (see below), whose sum is σ = 47950257180672. Its totient is φ = 18262621363200.
The previous prime is 31535134010131. The next prime is 31535134010143. The reversal of 31535134010133 is 33101043153513.
It is not a de Polignac number, because 31535134010133 - 21 = 31535134010131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31535134010094 and 31535134010103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31535134010131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3161923 + ... + 8547983.
It is an arithmetic number, because the mean of its divisors is an integer number (1498445536896).
Almost surely, 231535134010133 is an apocalyptic number.
It is an amenable number.
31535134010133 is a deficient number, since it is larger than the sum of its proper divisors (16415123170539).
31535134010133 is a wasteful number, since it uses less digits than its factorization.
31535134010133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5394925.
The product of its (nonzero) digits is 24300, while the sum is 33.
Adding to 31535134010133 its reverse (33101043153513), we get a palindrome (64636177163646).
The spelling of 31535134010133 in words is "thirty-one trillion, five hundred thirty-five billion, one hundred thirty-four million, ten thousand, one hundred thirty-three".
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