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31540214441 is a prime number
BaseRepresentation
bin11101010111111100…
…010111101010101001
310000102002110220101102
4131113330113222221
51004043243330231
622253412131145
72164411253651
oct352774275251
9100362426342
1031540214441
11124156a0a2a
126142906ab5
132c884c76a8
141752c19361
15c48e68acb
hex757f17aa9

31540214441 has 2 divisors, whose sum is σ = 31540214442. Its totient is φ = 31540214440.

The previous prime is 31540214417. The next prime is 31540214507. The reversal of 31540214441 is 14441204513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30431058025 + 1109156416 = 174445^2 + 33304^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31540214441 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (31540214141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15770107220 + 15770107221.

It is an arithmetic number, because the mean of its divisors is an integer number (15770107221).

Almost surely, 231540214441 is an apocalyptic number.

It is an amenable number.

31540214441 is a deficient number, since it is larger than the sum of its proper divisors (1).

31540214441 is an equidigital number, since it uses as much as digits as its factorization.

31540214441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7680, while the sum is 29.

Adding to 31540214441 its reverse (14441204513), we get a palindrome (45981418954).

The spelling of 31540214441 in words is "thirty-one billion, five hundred forty million, two hundred fourteen thousand, four hundred forty-one".