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31545083844097 is a prime number
BaseRepresentation
bin1110010110000101010011…
…00001000101011000000001
311010200200101010112110202021
413023002221201011120001
513113313312431002342
6151031340024121441
76434025404356405
oct713025141053001
9133620333473667
1031545083844097
11a0622164a682a
123655794906281
13147a8c4c41985
147b0b0c46d105
1539a860124567
hex1cb0a9845601

31545083844097 has 2 divisors, whose sum is σ = 31545083844098. Its totient is φ = 31545083844096.

The previous prime is 31545083844059. The next prime is 31545083844107. The reversal of 31545083844097 is 79044838054513.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30692940694641 + 852143149456 = 5540121^2 + 923116^2 .

It is a cyclic number.

It is not a de Polignac number, because 31545083844097 - 211 = 31545083842049 is a prime.

It is a super-2 number, since 2×315450838440972 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (31545083844697) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15772541922048 + 15772541922049.

It is an arithmetic number, because the mean of its divisors is an integer number (15772541922049).

Almost surely, 231545083844097 is an apocalyptic number.

It is an amenable number.

31545083844097 is a deficient number, since it is larger than the sum of its proper divisors (1).

31545083844097 is an equidigital number, since it uses as much as digits as its factorization.

31545083844097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 58060800, while the sum is 61.

The spelling of 31545083844097 in words is "thirty-one trillion, five hundred forty-five billion, eighty-three million, eight hundred forty-four thousand, ninety-seven".