31545300013 has 4 divisors (see below), whose sum is σ = 32562890368. Its totient is φ = 30527709660.

The previous prime is 31545299999. The next prime is 31545300023. The reversal of 31545300013 is 31000354513.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31000354513 = 61 ⋅508202533.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-31545300013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31545300023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 508795131 + ... + 508795192.

It is an arithmetic number, because the mean of its divisors is an integer number (8140722592).

Almost surely, 2^31545300013 is an apocalyptic number.

It is an amenable number.

31545300013 is a deficient number, since it is larger than the sum of its proper divisors (1017590355).

31545300013 is a wasteful number, since it uses less digits than its factorization.

31545300013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1017590354.

The product of its (nonzero) digits is 2700, while the sum is 25.

Adding to 31545300013 its reverse (31000354513), we get a palindrome (62545654526).

The spelling of 31545300013 in words is "thirty-one billion, five hundred forty-five million, three hundred thousand, thirteen".