Base | Representation |
---|---|
bin | 100011110111001110010000… |
… | …1110111010010110001011111 |
3 | 1112100221000102010021222110221 |
4 | 1013232130201313102301133 |
5 | 312321340301432213010 |
6 | 3034525042155142211 |
7 | 123305505120031552 |
oct | 10756344167226137 |
9 | 1470830363258427 |
10 | 315453031132255 |
11 | 91570974259a25 |
12 | 2b468ab1a44967 |
13 | 10703129997313 |
14 | 57c80185cc699 |
15 | 26709cd404dda |
hex | 11ee721dd2c5f |
315453031132255 has 32 divisors (see below), whose sum is σ = 379256506449408. Its totient is φ = 251887700534400.
The previous prime is 315453031132223. The next prime is 315453031132277. The reversal of 315453031132255 is 552231130354513.
It is not a de Polignac number, because 315453031132255 - 25 = 315453031132223 is a prime.
It is a super-2 number, since 2×3154530311322552 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 51452130540 + ... + 51452136670.
It is an arithmetic number, because the mean of its divisors is an integer number (11851765826544).
Almost surely, 2315453031132255 is an apocalyptic number.
315453031132255 is a deficient number, since it is larger than the sum of its proper divisors (63803475317153).
315453031132255 is a wasteful number, since it uses less digits than its factorization.
315453031132255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13887.
The product of its (nonzero) digits is 810000, while the sum is 43.
Adding to 315453031132255 its reverse (552231130354513), we get a palindrome (867684161486768).
The spelling of 315453031132255 in words is "three hundred fifteen trillion, four hundred fifty-three billion, thirty-one million, one hundred thirty-two thousand, two hundred fifty-five".
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