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31552514041 is a prime number
BaseRepresentation
bin11101011000101011…
…010010011111111001
310000102221121210021011
4131120223102133321
51004104420422131
622254531513521
72164620641566
oct353053223771
9100387553234
1031552514041
1112421631894
126146a588a1
132c8ac12b69
1417546db86d
15c4a0980b1
hex758ad27f9

31552514041 has 2 divisors, whose sum is σ = 31552514042. Its totient is φ = 31552514040.

The previous prime is 31552513997. The next prime is 31552514057. The reversal of 31552514041 is 14041525513.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16155426816 + 15397087225 = 127104^2 + 124085^2 .

It is a cyclic number.

It is not a de Polignac number, because 31552514041 - 217 = 31552382969 is a prime.

It is a super-5 number, since 5×315525140415 (a number of 54 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 31552513994 and 31552514012.

It is not a weakly prime, because it can be changed into another prime (31552544041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15776257020 + 15776257021.

It is an arithmetic number, because the mean of its divisors is an integer number (15776257021).

Almost surely, 231552514041 is an apocalyptic number.

It is an amenable number.

31552514041 is a deficient number, since it is larger than the sum of its proper divisors (1).

31552514041 is an equidigital number, since it uses as much as digits as its factorization.

31552514041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 31.

The spelling of 31552514041 in words is "thirty-one billion, five hundred fifty-two million, five hundred fourteen thousand, forty-one".