Search a number
-
+
315550661040401 is a prime number
BaseRepresentation
bin100011110111111011101110…
…1000011110101100100010001
31112101021100102010012011220212
41013233313131003311210101
5312324440223211243101
63035041550015013505
7123315532354410353
oct10757673503654421
91471240363164825
10315550661040401
11915a931384aa26
122b4839b9b0a295
131070c3b8460337
1457cca3a9770d3
1526732e45251bb
hex11efddd0f5911

315550661040401 has 2 divisors, whose sum is σ = 315550661040402. Its totient is φ = 315550661040400.

The previous prime is 315550661040343. The next prime is 315550661040431. The reversal of 315550661040401 is 104040166055513.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 298480873006801 + 17069788033600 = 17276599^2 + 4131560^2 .

It is an emirp because it is prime and its reverse (104040166055513) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 315550661040401 - 222 = 315550656846097 is a prime.

It is not a weakly prime, because it can be changed into another prime (315550661040431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157775330520200 + 157775330520201.

It is an arithmetic number, because the mean of its divisors is an integer number (157775330520201).

Almost surely, 2315550661040401 is an apocalyptic number.

It is an amenable number.

315550661040401 is a deficient number, since it is larger than the sum of its proper divisors (1).

315550661040401 is an equidigital number, since it uses as much as digits as its factorization.

315550661040401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216000, while the sum is 41.

The spelling of 315550661040401 in words is "three hundred fifteen trillion, five hundred fifty billion, six hundred sixty-one million, forty thousand, four hundred one".