Base | Representation |
---|---|
bin | 1001001100100001100… |
… | …00111101011011100001 |
3 | 1010012112220001102222202 |
4 | 10212100300331123201 |
5 | 20134042102204431 |
6 | 401052312342545 |
7 | 31553550204653 |
oct | 4462060753341 |
9 | 1105486042882 |
10 | 315961366241 |
11 | 111aa8a54a74 |
12 | 5129a9a4a55 |
13 | 23a448a9111 |
14 | 11414cd86d3 |
15 | 8343ac28cb |
hex | 4990c3d6e1 |
315961366241 has 4 divisors (see below), whose sum is σ = 317549112000. Its totient is φ = 314373620484.
The previous prime is 315961366219. The next prime is 315961366271. The reversal of 315961366241 is 142663169513.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 315961366241 - 214 = 315961349857 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (315961366271) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 793872581 + ... + 793872978.
It is an arithmetic number, because the mean of its divisors is an integer number (79387278000).
Almost surely, 2315961366241 is an apocalyptic number.
It is an amenable number.
315961366241 is a deficient number, since it is larger than the sum of its proper divisors (1587745759).
315961366241 is a wasteful number, since it uses less digits than its factorization.
315961366241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1587745758.
The product of its digits is 699840, while the sum is 47.
The spelling of 315961366241 in words is "three hundred fifteen billion, nine hundred sixty-one million, three hundred sixty-six thousand, two hundred forty-one".
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