Base | Representation |
---|---|
bin | 1001001100110010100… |
… | …01111100010010100011 |
3 | 1010012220211212200021222 |
4 | 10212121101330102203 |
5 | 20134340140330201 |
6 | 401114414405255 |
7 | 31560233423351 |
oct | 4463121742243 |
9 | 1105824780258 |
10 | 316104230051 |
11 | 112071662735 |
12 | 5131a80082b |
13 | 23a68379b0c |
14 | 11429c867d1 |
15 | 83513e291b |
hex | 499947c4a3 |
316104230051 has 2 divisors, whose sum is σ = 316104230052. Its totient is φ = 316104230050.
The previous prime is 316104230011. The next prime is 316104230059. The reversal of 316104230051 is 150032401613.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 316104230051 - 210 = 316104229027 is a prime.
It is a super-2 number, since 2×3161042300512 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 316104230051.
It is not a weakly prime, because it can be changed into another prime (316104230059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158052115025 + 158052115026.
It is an arithmetic number, because the mean of its divisors is an integer number (158052115026).
Almost surely, 2316104230051 is an apocalyptic number.
316104230051 is a deficient number, since it is larger than the sum of its proper divisors (1).
316104230051 is an equidigital number, since it uses as much as digits as its factorization.
316104230051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 316104230051 its reverse (150032401613), we get a palindrome (466136631664).
The spelling of 316104230051 in words is "three hundred sixteen billion, one hundred four million, two hundred thirty thousand, fifty-one".
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