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316110505793 is a prime number
BaseRepresentation
bin1001001100110011010…
…01111000011101000001
31010012221021200111222212
410212121221320131001
520134343242141133
6401115201111505
731560340652105
oct4463151703501
91105837614885
10316110505793
111120751597a5
1251320928595
1323a69766484
141142aa3b905
158351c32148
hex4999a78741

316110505793 has 2 divisors, whose sum is σ = 316110505794. Its totient is φ = 316110505792.

The previous prime is 316110505787. The next prime is 316110505819. The reversal of 316110505793 is 397505011613.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 307217449984 + 8893055809 = 554272^2 + 94303^2 .

It is a cyclic number.

It is not a de Polignac number, because 316110505793 - 26 = 316110505729 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 316110505793.

It is not a weakly prime, because it can be changed into another prime (316110585793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158055252896 + 158055252897.

It is an arithmetic number, because the mean of its divisors is an integer number (158055252897).

Almost surely, 2316110505793 is an apocalyptic number.

It is an amenable number.

316110505793 is a deficient number, since it is larger than the sum of its proper divisors (1).

316110505793 is an equidigital number, since it uses as much as digits as its factorization.

316110505793 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 85050, while the sum is 41.

The spelling of 316110505793 in words is "three hundred sixteen billion, one hundred ten million, five hundred five thousand, seven hundred ninety-three".