Base | Representation |
---|---|
bin | 101110000000001001010… |
… | …100010111110101110011 |
3 | 102012012202002212002112111 |
4 | 232000021110113311303 |
5 | 403243221034442311 |
6 | 10420131555110151 |
7 | 444251530616446 |
oct | 56001124276563 |
9 | 12165662762474 |
10 | 3161252265331 |
11 | 1009752543366 |
12 | 430808ba2357 |
13 | 19c149360514 |
14 | ad010c6365d |
15 | 573710e2d21 |
hex | 2e009517d73 |
3161252265331 has 2 divisors, whose sum is σ = 3161252265332. Its totient is φ = 3161252265330.
The previous prime is 3161252265317. The next prime is 3161252265463. The reversal of 3161252265331 is 1335622521613.
It is a weak prime.
It is an emirp because it is prime and its reverse (1335622521613) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3161252265331 - 25 = 3161252265299 is a prime.
It is a super-2 number, since 2×31612522653312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3161258265331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1580626132665 + 1580626132666.
It is an arithmetic number, because the mean of its divisors is an integer number (1580626132666).
Almost surely, 23161252265331 is an apocalyptic number.
3161252265331 is a deficient number, since it is larger than the sum of its proper divisors (1).
3161252265331 is an equidigital number, since it uses as much as digits as its factorization.
3161252265331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 194400, while the sum is 40.
Adding to 3161252265331 its reverse (1335622521613), we get a palindrome (4496874786944).
The spelling of 3161252265331 in words is "three trillion, one hundred sixty-one billion, two hundred fifty-two million, two hundred sixty-five thousand, three hundred thirty-one".
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