Base | Representation |
---|---|
bin | 101110000000001110110… |
… | …011100111000010011101 |
3 | 102012012222112002222102001 |
4 | 232000032303213002131 |
5 | 403243413122341000 |
6 | 10420145044402301 |
7 | 444254026343206 |
oct | 56001663470235 |
9 | 12165875088361 |
10 | 3161344340125 |
11 | 100979a511534 |
12 | 4308339a6391 |
13 | 19c16245a94a |
14 | ad01d1905ad |
15 | 5737922e46a |
hex | 2e00ece709d |
3161344340125 has 8 divisors (see below), whose sum is σ = 3945357736632. Its totient is φ = 2529075472000.
The previous prime is 3161344340093. The next prime is 3161344340159. The reversal of 3161344340125 is 5210434431613.
It can be written as a sum of positive squares in 4 ways, for example, as 739206172441 + 2422138167684 = 859771^2 + 1556322^2 .
It is not a de Polignac number, because 3161344340125 - 25 = 3161344340093 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12645377236 + ... + 12645377485.
It is an arithmetic number, because the mean of its divisors is an integer number (493169717079).
Almost surely, 23161344340125 is an apocalyptic number.
It is an amenable number.
3161344340125 is a deficient number, since it is larger than the sum of its proper divisors (784013396507).
3161344340125 is an equidigital number, since it uses as much as digits as its factorization.
3161344340125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25290754736 (or 25290754726 counting only the distinct ones).
The product of its (nonzero) digits is 103680, while the sum is 37.
Adding to 3161344340125 its reverse (5210434431613), we get a palindrome (8371778771738).
The spelling of 3161344340125 in words is "three trillion, one hundred sixty-one billion, three hundred forty-four million, three hundred forty thousand, one hundred twenty-five".
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