Base | Representation |
---|---|
bin | 1001001100111101010… |
… | …01011101011111111111 |
3 | 1010020011010022202121202 |
4 | 10212132221131133333 |
5 | 20140031214001341 |
6 | 401131352450115 |
7 | 31562406022055 |
oct | 4463651353777 |
9 | 1106133282552 |
10 | 316194281471 |
11 | 1121084796a2 |
12 | 513449a993b |
13 | 23a80c19293 |
14 | 11437c081d5 |
15 | 835927e79b |
hex | 499ea5d7ff |
316194281471 has 4 divisors (see below), whose sum is σ = 321377794344. Its totient is φ = 311010768600.
The previous prime is 316194281341. The next prime is 316194281483. The reversal of 316194281471 is 174182491613.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 174182491613 = 13 ⋅13398653201.
It is a cyclic number.
It is not a de Polignac number, because 316194281471 - 226 = 316127172607 is a prime.
It is a super-3 number, since 3×3161942814713 (a number of 35 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (316194281071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2591756345 + ... + 2591756466.
It is an arithmetic number, because the mean of its divisors is an integer number (80344448586).
Almost surely, 2316194281471 is an apocalyptic number.
316194281471 is a deficient number, since it is larger than the sum of its proper divisors (5183512873).
316194281471 is an equidigital number, since it uses as much as digits as its factorization.
316194281471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5183512872.
The product of its digits is 290304, while the sum is 47.
The spelling of 316194281471 in words is "three hundred sixteen billion, one hundred ninety-four million, two hundred eighty-one thousand, four hundred seventy-one".
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