Base | Representation |
---|---|
bin | 100011111101011111011011… |
… | …1010010000001110011111111 |
3 | 1112110222101002120001021121001 |
4 | 1013322332313102001303333 |
5 | 312424444130014430210 |
6 | 3040424520055551131 |
7 | 123424653651363511 |
oct | 10772766722016377 |
9 | 1473871076037531 |
10 | 316314531405055 |
11 | 9187326a747957 |
12 | 2b587a6068b4a7 |
13 | 1076644215a351 |
14 | 58179c277bbb1 |
15 | 26881009ea03a |
hex | 11fafb7481cff |
316314531405055 has 32 divisors (see below), whose sum is σ = 409719387188160. Its totient is φ = 233646574510080.
The previous prime is 316314531405023. The next prime is 316314531405071. The reversal of 316314531405055 is 550504135413613.
It is not a de Polignac number, because 316314531405055 - 25 = 316314531405023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 316314531404996 and 316314531405014.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 37755694 + ... + 45366523.
It is an arithmetic number, because the mean of its divisors is an integer number (12803730849630).
Almost surely, 2316314531405055 is an apocalyptic number.
316314531405055 is a deficient number, since it is larger than the sum of its proper divisors (93404855783105).
316314531405055 is a wasteful number, since it uses less digits than its factorization.
316314531405055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 83123259.
The product of its (nonzero) digits is 1620000, while the sum is 46.
Adding to 316314531405055 its reverse (550504135413613), we get a palindrome (866818666818668).
The spelling of 316314531405055 in words is "three hundred sixteen trillion, three hundred fourteen billion, five hundred thirty-one million, four hundred five thousand, fifty-five".
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