Base | Representation |
---|---|
bin | 1001001101010011011… |
… | …11110001100011111001 |
3 | 1010020122002200221001101 |
4 | 10212221233301203321 |
5 | 20140421401022011 |
6 | 401202043451401 |
7 | 31600126521055 |
oct | 4465157614371 |
9 | 1106562627041 |
10 | 316380485881 |
11 | 1121a3599839 |
12 | 51397226b61 |
13 | 23ab06831c5 |
14 | 11454838c65 |
15 | 836a7b12c1 |
hex | 49a9bf18f9 |
316380485881 has 2 divisors, whose sum is σ = 316380485882. Its totient is φ = 316380485880.
The previous prime is 316380485857. The next prime is 316380485933. The reversal of 316380485881 is 188584083613.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 188777215225 + 127603270656 = 434485^2 + 357216^2 .
It is a cyclic number.
It is not a de Polignac number, because 316380485881 - 25 = 316380485849 is a prime.
It is a super-2 number, since 2×3163804858812 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (316380485581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158190242940 + 158190242941.
It is an arithmetic number, because the mean of its divisors is an integer number (158190242941).
Almost surely, 2316380485881 is an apocalyptic number.
It is an amenable number.
316380485881 is a deficient number, since it is larger than the sum of its proper divisors (1).
316380485881 is an equidigital number, since it uses as much as digits as its factorization.
316380485881 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4423680, while the sum is 55.
The spelling of 316380485881 in words is "three hundred sixteen billion, three hundred eighty million, four hundred eighty-five thousand, eight hundred eighty-one".
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