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31656068497 is a prime number
BaseRepresentation
bin11101011110110110…
…010100010110010001
310000201011110220021101
4131132312110112101
51004312423142442
622313111224401
72200316066614
oct353666242621
9100634426241
1031656068497
1112475030889
126175678101
132ca64cc4a1
14176437617b
15c54200cb7
hex75ed94591

31656068497 has 2 divisors, whose sum is σ = 31656068498. Its totient is φ = 31656068496.

The previous prime is 31656068393. The next prime is 31656068519. The reversal of 31656068497 is 79486065613.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23004092241 + 8651976256 = 151671^2 + 93016^2 .

It is an emirp because it is prime and its reverse (79486065613) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31656068497 - 27 = 31656068369 is a prime.

It is not a weakly prime, because it can be changed into another prime (31656068597) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15828034248 + 15828034249.

It is an arithmetic number, because the mean of its divisors is an integer number (15828034249).

Almost surely, 231656068497 is an apocalyptic number.

It is an amenable number.

31656068497 is a deficient number, since it is larger than the sum of its proper divisors (1).

31656068497 is an equidigital number, since it uses as much as digits as its factorization.

31656068497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6531840, while the sum is 55.

The spelling of 31656068497 in words is "thirty-one billion, six hundred fifty-six million, sixty-eight thousand, four hundred ninety-seven".