Base | Representation |
---|---|
bin | 11101011110110110… |
… | …010100010110010001 |
3 | 10000201011110220021101 |
4 | 131132312110112101 |
5 | 1004312423142442 |
6 | 22313111224401 |
7 | 2200316066614 |
oct | 353666242621 |
9 | 100634426241 |
10 | 31656068497 |
11 | 12475030889 |
12 | 6175678101 |
13 | 2ca64cc4a1 |
14 | 176437617b |
15 | c54200cb7 |
hex | 75ed94591 |
31656068497 has 2 divisors, whose sum is σ = 31656068498. Its totient is φ = 31656068496.
The previous prime is 31656068393. The next prime is 31656068519. The reversal of 31656068497 is 79486065613.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23004092241 + 8651976256 = 151671^2 + 93016^2 .
It is an emirp because it is prime and its reverse (79486065613) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31656068497 - 27 = 31656068369 is a prime.
It is not a weakly prime, because it can be changed into another prime (31656068597) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15828034248 + 15828034249.
It is an arithmetic number, because the mean of its divisors is an integer number (15828034249).
Almost surely, 231656068497 is an apocalyptic number.
It is an amenable number.
31656068497 is a deficient number, since it is larger than the sum of its proper divisors (1).
31656068497 is an equidigital number, since it uses as much as digits as its factorization.
31656068497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6531840, while the sum is 55.
The spelling of 31656068497 in words is "thirty-one billion, six hundred fifty-six million, sixty-eight thousand, four hundred ninety-seven".
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