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3166740541241 is a prime number
BaseRepresentation
bin101110000101010000011…
…100011110111100111001
3102012201220121000101201122
4232011100130132330321
5403340441034304431
610422440331555025
7444534532321034
oct56052034367471
912181817011648
103166740541241
11101100952a282
1243189abbba75
1319c8123ca964
14ad3b1b0801b
1557592d48a7b
hex2e15071ef39

3166740541241 has 2 divisors, whose sum is σ = 3166740541242. Its totient is φ = 3166740541240.

The previous prime is 3166740541229. The next prime is 3166740541277. The reversal of 3166740541241 is 1421450476613.

3166740541241 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3090124515625 + 76616025616 = 1757875^2 + 276796^2 .

It is a cyclic number.

It is not a de Polignac number, because 3166740541241 - 210 = 3166740540217 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 3166740541192 and 3166740541201.

It is not a weakly prime, because it can be changed into another prime (3166740541541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1583370270620 + 1583370270621.

It is an arithmetic number, because the mean of its divisors is an integer number (1583370270621).

Almost surely, 23166740541241 is an apocalyptic number.

It is an amenable number.

3166740541241 is a deficient number, since it is larger than the sum of its proper divisors (1).

3166740541241 is an equidigital number, since it uses as much as digits as its factorization.

3166740541241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 483840, while the sum is 44.

The spelling of 3166740541241 in words is "three trillion, one hundred sixty-six billion, seven hundred forty million, five hundred forty-one thousand, two hundred forty-one".