Base | Representation |
---|---|
bin | 1001001110011011011… |
… | …00001100000000100001 |
3 | 1010022012010102111202201 |
4 | 10213031230030000201 |
5 | 20143140240303114 |
6 | 401341545013201 |
7 | 31621101336565 |
oct | 4471554140041 |
9 | 1108163374681 |
10 | 316983525409 |
11 | 112482a33311 |
12 | 51525184201 |
13 | 23b785a4425 |
14 | 114b09736a5 |
15 | 83a36ce874 |
hex | 49cdb0c021 |
316983525409 has 2 divisors, whose sum is σ = 316983525410. Its totient is φ = 316983525408.
The previous prime is 316983525401. The next prime is 316983525437. The reversal of 316983525409 is 904525389613.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 307023485409 + 9960040000 = 554097^2 + 99800^2 .
It is a cyclic number.
It is not a de Polignac number, because 316983525409 - 23 = 316983525401 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 316983525409.
It is not a weakly prime, because it can be changed into another prime (316983525401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158491762704 + 158491762705.
It is an arithmetic number, because the mean of its divisors is an integer number (158491762705).
Almost surely, 2316983525409 is an apocalyptic number.
It is an amenable number.
316983525409 is a deficient number, since it is larger than the sum of its proper divisors (1).
316983525409 is an equidigital number, since it uses as much as digits as its factorization.
316983525409 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6998400, while the sum is 55.
The spelling of 316983525409 in words is "three hundred sixteen billion, nine hundred eighty-three million, five hundred twenty-five thousand, four hundred nine".
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