Base | Representation |
---|---|
bin | 101110001000011000010… |
… | …110101100111100110001 |
3 | 102020001120100000120120001 |
4 | 232020120112230330301 |
5 | 403414323141001123 |
6 | 10424153222150001 |
7 | 445013616246601 |
oct | 56103026547461 |
9 | 12201510016501 |
10 | 3170094468913 |
11 | 101247a757829 |
12 | 432476282301 |
13 | 19cc28212048 |
14 | ad60d320c01 |
15 | 576dc5000ad |
hex | 2e2185acf31 |
3170094468913 has 2 divisors, whose sum is σ = 3170094468914. Its totient is φ = 3170094468912.
The previous prime is 3170094468907. The next prime is 3170094468943. The reversal of 3170094468913 is 3198644900713.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1598940018064 + 1571154450849 = 1264492^2 + 1253457^2 .
It is a cyclic number.
It is not a de Polignac number, because 3170094468913 - 217 = 3170094337841 is a prime.
It is not a weakly prime, because it can be changed into another prime (3170094468943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1585047234456 + 1585047234457.
It is an arithmetic number, because the mean of its divisors is an integer number (1585047234457).
Almost surely, 23170094468913 is an apocalyptic number.
It is an amenable number.
3170094468913 is a deficient number, since it is larger than the sum of its proper divisors (1).
3170094468913 is an equidigital number, since it uses as much as digits as its factorization.
3170094468913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3919104, while the sum is 55.
The spelling of 3170094468913 in words is "three trillion, one hundred seventy billion, ninety-four million, four hundred sixty-eight thousand, nine hundred thirteen".
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