Base | Representation |
---|---|
bin | 11101100010000111… |
… | …111011100010011001 |
3 | 10000211222212120121022 |
4 | 131202013323202121 |
5 | 1004421010021423 |
6 | 22322353052225 |
7 | 2201554124636 |
oct | 354207734231 |
9 | 100758776538 |
10 | 31711017113 |
11 | 124a3051566 |
12 | 618bb57075 |
13 | 2cb49cb169 |
14 | 176b79b18d |
15 | c58e56dc8 |
hex | 7621fb899 |
31711017113 has 2 divisors, whose sum is σ = 31711017114. Its totient is φ = 31711017112.
The previous prime is 31711017109. The next prime is 31711017127. The reversal of 31711017113 is 31171011713.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 28664860249 + 3046156864 = 169307^2 + 55192^2 .
It is an emirp because it is prime and its reverse (31171011713) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31711017113 - 22 = 31711017109 is a prime.
It is not a weakly prime, because it can be changed into another prime (31711017103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15855508556 + 15855508557.
It is an arithmetic number, because the mean of its divisors is an integer number (15855508557).
Almost surely, 231711017113 is an apocalyptic number.
It is an amenable number.
31711017113 is a deficient number, since it is larger than the sum of its proper divisors (1).
31711017113 is an equidigital number, since it uses as much as digits as its factorization.
31711017113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 441, while the sum is 26.
Adding to 31711017113 its reverse (31171011713), we get a palindrome (62882028826).
The spelling of 31711017113 in words is "thirty-one billion, seven hundred eleven million, seventeen thousand, one hundred thirteen".
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