Base | Representation |
---|---|
bin | 100100000101000000000111… |
… | …0011011000011110010100001 |
3 | 1112121122001112010022121001002 |
4 | 1020022000032123003302201 |
5 | 313043402204044310111 |
6 | 3042535033424321345 |
7 | 123562356116643236 |
oct | 11012001633036241 |
9 | 1477561463277032 |
10 | 317346785541281 |
11 | 9213101a251781 |
12 | 2b713b24473255 |
13 | 1080c89a7c55a2 |
14 | 585194875d78d |
15 | 26a4db8bec63b |
hex | 120a00e6c3ca1 |
317346785541281 has 2 divisors, whose sum is σ = 317346785541282. Its totient is φ = 317346785541280.
The previous prime is 317346785541251. The next prime is 317346785541337. The reversal of 317346785541281 is 182145587643713.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 300411223140625 + 16935562400656 = 17332375^2 + 4115284^2 .
It is a cyclic number.
It is not a de Polignac number, because 317346785541281 - 222 = 317346781346977 is a prime.
It is a super-2 number, since 2×3173467855412812 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (317346785541211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158673392770640 + 158673392770641.
It is an arithmetic number, because the mean of its divisors is an integer number (158673392770641).
Almost surely, 2317346785541281 is an apocalyptic number.
It is an amenable number.
317346785541281 is a deficient number, since it is larger than the sum of its proper divisors (1).
317346785541281 is an equidigital number, since it uses as much as digits as its factorization.
317346785541281 is an evil number, because the sum of its binary digits is even.
The product of its digits is 135475200, while the sum is 65.
The spelling of 317346785541281 in words is "three hundred seventeen trillion, three hundred forty-six billion, seven hundred eighty-five million, five hundred forty-one thousand, two hundred eighty-one".
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