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3180255041 is a prime number
BaseRepresentation
bin1011110110001110…
…1101011101000001
322012122012200202202
42331203231131001
523003121130131
61243323522545
7141544502405
oct27543553501
98178180682
103180255041
111392197757
12749089455
133b8b47522
14222529105
151392ecbcb
hexbd8ed741

3180255041 has 2 divisors, whose sum is σ = 3180255042. Its totient is φ = 3180255040.

The previous prime is 3180255007. The next prime is 3180255049. The reversal of 3180255041 is 1405520813.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3151138225 + 29116816 = 56135^2 + 5396^2 .

It is a cyclic number.

It is not a de Polignac number, because 3180255041 - 218 = 3179992897 is a prime.

It is a super-3 number, since 3×31802550413 (a number of 29 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 3180254995 and 3180255013.

It is not a weakly prime, because it can be changed into another prime (3180255049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1590127520 + 1590127521.

It is an arithmetic number, because the mean of its divisors is an integer number (1590127521).

Almost surely, 23180255041 is an apocalyptic number.

It is an amenable number.

3180255041 is a deficient number, since it is larger than the sum of its proper divisors (1).

3180255041 is an equidigital number, since it uses as much as digits as its factorization.

3180255041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 29.

The square root of 3180255041 is about 56393.7500171783. The cubic root of 3180255041 is about 1470.5754670714.

Adding to 3180255041 its reverse (1405520813), we get a palindrome (4585775854).

The spelling of 3180255041 in words is "three billion, one hundred eighty million, two hundred fifty-five thousand, forty-one".