Search a number
-
+
318854812433 is a prime number
BaseRepresentation
bin1001010001111010011…
…10100101001100010001
31010111000112120201222112
410220331032211030101
520211003312444213
6402251353115105
732015343121103
oct4507516451421
91114015521875
10318854812433
11113253257a13
12519679b8a95
13240b6193a61
141160b2c5573
158462b19ea8
hex4a3d3a5311

318854812433 has 2 divisors, whose sum is σ = 318854812434. Its totient is φ = 318854812432.

The previous prime is 318854812343. The next prime is 318854812447. The reversal of 318854812433 is 334218458813.

Together with previous prime (318854812343) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 315897954304 + 2956858129 = 562048^2 + 54377^2 .

It is a cyclic number.

It is not a de Polignac number, because 318854812433 - 230 = 317781070609 is a prime.

It is a super-2 number, since 2×3188548124332 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (318854812483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 159427406216 + 159427406217.

It is an arithmetic number, because the mean of its divisors is an integer number (159427406217).

Almost surely, 2318854812433 is an apocalyptic number.

It is an amenable number.

318854812433 is a deficient number, since it is larger than the sum of its proper divisors (1).

318854812433 is an equidigital number, since it uses as much as digits as its factorization.

318854812433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2211840, while the sum is 50.

The spelling of 318854812433 in words is "three hundred eighteen billion, eight hundred fifty-four million, eight hundred twelve thousand, four hundred thirty-three".