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3200004113 is a prime number
BaseRepresentation
bin1011111010111100…
…0011000000010001
322021000101001101212
42332233003000101
523023200112423
61245311105505
7142204405025
oct27657030021
98230331355
103200004113
1113a23564a9
12753812295
133bcc70677
14224dca385
1513adee578
hexbebc3011

3200004113 has 2 divisors, whose sum is σ = 3200004114. Its totient is φ = 3200004112.

The previous prime is 3200004107. The next prime is 3200004133. The reversal of 3200004113 is 3114000023.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1635959809 + 1564044304 = 40447^2 + 39548^2 .

It is an emirp because it is prime and its reverse (3114000023) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3200004113 - 24 = 3200004097 is a prime.

It is not a weakly prime, because it can be changed into another prime (3200004133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600002056 + 1600002057.

It is an arithmetic number, because the mean of its divisors is an integer number (1600002057).

Almost surely, 23200004113 is an apocalyptic number.

It is an amenable number.

3200004113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3200004113 is an equidigital number, since it uses as much as digits as its factorization.

3200004113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 14.

The square root of 3200004113 is about 56568.5788490395. The cubic root of 3200004113 is about 1473.6132308068.

Adding to 3200004113 its reverse (3114000023), we get a palindrome (6314004136).

The spelling of 3200004113 in words is "three billion, two hundred million, four thousand, one hundred thirteen".