Base | Representation |
---|---|
bin | 101110100100010100111… |
… | …100101110100010100111 |
3 | 102022221000121200010121002 |
4 | 232210110330232202213 |
5 | 404412302114132421 |
6 | 10450035005543515 |
7 | 450125341015121 |
oct | 56442474564247 |
9 | 12287017603532 |
10 | 3200102099111 |
11 | 1024179232505 |
12 | 43824b874b9b |
13 | 1a29cb049148 |
14 | b0c58794211 |
15 | 58396b34b0b |
hex | 2e914f2e8a7 |
3200102099111 has 12 divisors (see below), whose sum is σ = 3434637047400. Its totient is φ = 2980291319568.
The previous prime is 3200102099087. The next prime is 3200102099113. The reversal of 3200102099111 is 1119902010023.
It is a de Polignac number, because none of the positive numbers 2k-3200102099111 is a prime.
It is a super-4 number, since 4×32001020991114 (a number of 51 digits) contains 4444 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3200102099113) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 75101996 + ... + 75144593.
It is an arithmetic number, because the mean of its divisors is an integer number (286219753950).
Almost surely, 23200102099111 is an apocalyptic number.
3200102099111 is a deficient number, since it is larger than the sum of its proper divisors (234534948289).
3200102099111 is a wasteful number, since it uses less digits than its factorization.
3200102099111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 150246686 (or 150246667 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 29.
The spelling of 3200102099111 in words is "three trillion, two hundred billion, one hundred two million, ninety-nine thousand, one hundred eleven".
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