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3200103000113 is a prime number
BaseRepresentation
bin101110100100010101000…
…000001010100000110001
3102022221000200100220112112
4232210111000022200301
5404412302332000423
610450035041135105
7450125351460005
oct56442500124061
912287020326475
103200103000113
111024179798438
1243825002a495
131a29cb2a3296
14b0c5894a705
1558396c61a78
hex2e91500a831

3200103000113 has 2 divisors, whose sum is σ = 3200103000114. Its totient is φ = 3200103000112.

The previous prime is 3200103000067. The next prime is 3200103000169. The reversal of 3200103000113 is 3110003010023.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2576432686129 + 623670313984 = 1605127^2 + 789728^2 .

It is a cyclic number.

It is not a de Polignac number, because 3200103000113 - 218 = 3200102737969 is a prime.

It is a super-2 number, since 2×32001030001132 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3200103000713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600051500056 + 1600051500057.

It is an arithmetic number, because the mean of its divisors is an integer number (1600051500057).

Almost surely, 23200103000113 is an apocalyptic number.

It is an amenable number.

3200103000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3200103000113 is an equidigital number, since it uses as much as digits as its factorization.

3200103000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 3200103000113 its reverse (3110003010023), we get a palindrome (6310106010136).

The spelling of 3200103000113 in words is "three trillion, two hundred billion, one hundred three million, one hundred thirteen", and thus it is an aban number.