Base | Representation |
---|---|
bin | 11101110011011011… |
… | …101010010100000001 |
3 | 10001121020021122221022 |
4 | 131303123222110001 |
5 | 1011014324331423 |
6 | 22411245035225 |
7 | 2212011300302 |
oct | 356333522401 |
9 | 101536248838 |
10 | 32001402113 |
11 | 12631a5906a |
12 | 6251255b15 |
13 | 302cc106c5 |
14 | 179818a7a9 |
15 | c746b6dc8 |
hex | 7736ea501 |
32001402113 has 2 divisors, whose sum is σ = 32001402114. Its totient is φ = 32001402112.
The previous prime is 32001402101. The next prime is 32001402151. The reversal of 32001402113 is 31120410023.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20624406544 + 11376995569 = 143612^2 + 106663^2 .
It is a cyclic number.
It is not a de Polignac number, because 32001402113 - 226 = 31934293249 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 32001402091 and 32001402100.
It is not a weakly prime, because it can be changed into another prime (32001402163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16000701056 + 16000701057.
It is an arithmetic number, because the mean of its divisors is an integer number (16000701057).
Almost surely, 232001402113 is an apocalyptic number.
It is an amenable number.
32001402113 is a deficient number, since it is larger than the sum of its proper divisors (1).
32001402113 is an equidigital number, since it uses as much as digits as its factorization.
32001402113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 32001402113 its reverse (31120410023), we get a palindrome (63121812136).
The spelling of 32001402113 in words is "thirty-two billion, one million, four hundred two thousand, one hundred thirteen".
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