Base | Representation |
---|---|
bin | 1001010100000111111… |
… | …11011000101100101001 |
3 | 1010121002021111200211212 |
4 | 10222003333120230221 |
5 | 20220421223331213 |
6 | 403005243002505 |
7 | 32056640132504 |
oct | 4520377305451 |
9 | 1117067450755 |
10 | 320042011433 |
11 | 113802410111 |
12 | 52039509435 |
13 | 24245125781 |
14 | 116c0c4213b |
15 | 84d1e779a8 |
hex | 4a83fd8b29 |
320042011433 has 2 divisors, whose sum is σ = 320042011434. Its totient is φ = 320042011432.
The previous prime is 320042011423. The next prime is 320042011459. The reversal of 320042011433 is 334110240023.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 166568464384 + 153473547049 = 408128^2 + 391757^2 .
It is a cyclic number.
It is not a de Polignac number, because 320042011433 - 24 = 320042011417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 320042011399 and 320042011408.
It is not a weakly prime, because it can be changed into another prime (320042011423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160021005716 + 160021005717.
It is an arithmetic number, because the mean of its divisors is an integer number (160021005717).
Almost surely, 2320042011433 is an apocalyptic number.
It is an amenable number.
320042011433 is a deficient number, since it is larger than the sum of its proper divisors (1).
320042011433 is an equidigital number, since it uses as much as digits as its factorization.
320042011433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 320042011433 its reverse (334110240023), we get a palindrome (654152251456).
The spelling of 320042011433 in words is "three hundred twenty billion, forty-two million, eleven thousand, four hundred thirty-three".
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