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320045331401 is a prime number
BaseRepresentation
bin1001010100001000011…
…00000011001111001001
31010121002111202100222122
410222010030003033021
520220423101101101
6403005442101025
732060010300635
oct4520414031711
91117074670878
10320045331401
11113804278494
125203a64a775
1324245a18953
14116c1467dc5
1584d23d151b
hex4a843033c9

320045331401 has 2 divisors, whose sum is σ = 320045331402. Its totient is φ = 320045331400.

The previous prime is 320045331379. The next prime is 320045331421. The reversal of 320045331401 is 104133540023.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 295278126025 + 24767205376 = 543395^2 + 157376^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-320045331401 is a prime.

It is a super-3 number, since 3×3200453314013 (a number of 35 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (320045331421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160022665700 + 160022665701.

It is an arithmetic number, because the mean of its divisors is an integer number (160022665701).

Almost surely, 2320045331401 is an apocalyptic number.

It is an amenable number.

320045331401 is a deficient number, since it is larger than the sum of its proper divisors (1).

320045331401 is an equidigital number, since it uses as much as digits as its factorization.

320045331401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 26.

Adding to 320045331401 its reverse (104133540023), we get a palindrome (424178871424).

The spelling of 320045331401 in words is "three hundred twenty billion, forty-five million, three hundred thirty-one thousand, four hundred one".