Base | Representation |
---|---|
bin | 11101110100000001… |
… | …011111101011101001 |
3 | 10001121220221112202222 |
4 | 131310001133223221 |
5 | 1011024344220131 |
6 | 22412241403425 |
7 | 2212161505451 |
oct | 356401375351 |
9 | 101556845688 |
10 | 32011320041 |
11 | 126376125a8 |
12 | 6254639575 |
13 | 3031ca3abc |
14 | 179960cd61 |
15 | c754c587b |
hex | 77405fae9 |
32011320041 has 2 divisors, whose sum is σ = 32011320042. Its totient is φ = 32011320040.
The previous prime is 32011319999. The next prime is 32011320049. The reversal of 32011320041 is 14002311023.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31924755625 + 86564416 = 178675^2 + 9304^2 .
It is an emirp because it is prime and its reverse (14002311023) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32011320041 is a prime.
It is a super-2 number, since 2×320113200412 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (32011320049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16005660020 + 16005660021.
It is an arithmetic number, because the mean of its divisors is an integer number (16005660021).
Almost surely, 232011320041 is an apocalyptic number.
It is an amenable number.
32011320041 is a deficient number, since it is larger than the sum of its proper divisors (1).
32011320041 is an equidigital number, since it uses as much as digits as its factorization.
32011320041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 32011320041 its reverse (14002311023), we get a palindrome (46013631064).
The spelling of 32011320041 in words is "thirty-two billion, eleven million, three hundred twenty thousand, forty-one".
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