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32011320041 is a prime number
BaseRepresentation
bin11101110100000001…
…011111101011101001
310001121220221112202222
4131310001133223221
51011024344220131
622412241403425
72212161505451
oct356401375351
9101556845688
1032011320041
11126376125a8
126254639575
133031ca3abc
14179960cd61
15c754c587b
hex77405fae9

32011320041 has 2 divisors, whose sum is σ = 32011320042. Its totient is φ = 32011320040.

The previous prime is 32011319999. The next prime is 32011320049. The reversal of 32011320041 is 14002311023.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31924755625 + 86564416 = 178675^2 + 9304^2 .

It is an emirp because it is prime and its reverse (14002311023) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-32011320041 is a prime.

It is a super-2 number, since 2×320113200412 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (32011320049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16005660020 + 16005660021.

It is an arithmetic number, because the mean of its divisors is an integer number (16005660021).

Almost surely, 232011320041 is an apocalyptic number.

It is an amenable number.

32011320041 is a deficient number, since it is larger than the sum of its proper divisors (1).

32011320041 is an equidigital number, since it uses as much as digits as its factorization.

32011320041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 32011320041 its reverse (14002311023), we get a palindrome (46013631064).

The spelling of 32011320041 in words is "thirty-two billion, eleven million, three hundred twenty thousand, forty-one".