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320121121320000 = 263254711134373283
BaseRepresentation
bin100100011001001100000000…
…1101110001010110001000000
31112222110021120100112122212200
41020302120001232022301000
5313424331024024220000
63052501340220353200
7124266662544654630
oct11062300156126100
91488407510478780
10320121121320000
1193000672498a20
122baa174b9a5800
13109813a4ca9a70
145909d32cc86c0
152702141d43500
hex1232601b8ac40

320121121320000 has 6720 divisors, whose sum is σ = 1602507652601856. Its totient is φ = 58943324160000.

The previous prime is 320121121319971. The next prime is 320121121320029. The reversal of 320121121320000 is 23121121023.

320121121320000 is a `hidden beast` number, since 3 + 201 + 21 + 121 + 320 + 0 + 0 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (320121121319971) and next prime (320121121320029).

It is a tau number, because it is divible by the number of its divisors (6720).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 959 ways as a sum of consecutive naturals, for example, 1131170039859 + ... + 1131170040141.

Almost surely, 2320121121320000 is an apocalyptic number.

320121121320000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 320121121320000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (801253826300928).

320121121320000 is an abundant number, since it is smaller than the sum of its proper divisors (1282386531281856).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

320121121320000 is a wasteful number, since it uses less digits than its factorization.

320121121320000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 468 (or 440 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 320121121320000 its reverse (23121121023), we get a palindrome (320144242441023).

The spelling of 320121121320000 in words is "three hundred twenty trillion, one hundred twenty-one billion, one hundred twenty-one million, three hundred twenty thousand".