32013030113 has 2 divisors, whose sum is σ = 32013030114. Its totient is φ = 32013030112.

The previous prime is 32013030109. The next prime is 32013030149. The reversal of 32013030113 is 31103031023.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31014027664 + 999002449 = 176108^2 + 31607^2 .

It is an emirp because it is prime and its reverse (31103031023) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 32013030113 - 2² = 32013030109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 32013030091 and 32013030100.

It is not a weakly prime, because it can be changed into another prime (32013030103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16006515056 + 16006515057.

It is an arithmetic number, because the mean of its divisors is an integer number (16006515057).

Almost surely, 2^32013030113 is an apocalyptic number.

It is an amenable number.

32013030113 is a deficient number, since it is larger than the sum of its proper divisors (1).

32013030113 is an equidigital number, since it uses as much as digits as its factorization.

32013030113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 32013030113 its reverse (31103031023), we get a palindrome (63116061136).

The spelling of 32013030113 in words is "thirty-two billion, thirteen million, thirty thousand, one hundred thirteen".