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3201311219963 is a prime number
BaseRepresentation
bin101110100101011101000…
…001001010000011111011
3102100001010212211211120212
4232211131001022003323
5404422241133014323
610450355001341335
7450200322251603
oct56453501120373
912301125754525
103201311219963
1110247397a893a
1243852879784b
131a2b616b4c7c
14b0d311b9c03
1558417d72b78
hex2e95d04a0fb

3201311219963 has 2 divisors, whose sum is σ = 3201311219964. Its totient is φ = 3201311219962.

The previous prime is 3201311219879. The next prime is 3201311220049. The reversal of 3201311219963 is 3699121131023.

3201311219963 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (3699121131023) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3201311219963 - 28 = 3201311219707 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3201311219963.

It is not a weakly prime, because it can be changed into another prime (3201311219863) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600655609981 + 1600655609982.

It is an arithmetic number, because the mean of its divisors is an integer number (1600655609982).

Almost surely, 23201311219963 is an apocalyptic number.

3201311219963 is a deficient number, since it is larger than the sum of its proper divisors (1).

3201311219963 is an equidigital number, since it uses as much as digits as its factorization.

3201311219963 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 52488, while the sum is 41.

The spelling of 3201311219963 in words is "three trillion, two hundred one billion, three hundred eleven million, two hundred nineteen thousand, nine hundred sixty-three".