Base | Representation |
---|---|
bin | 101110100101011110010… |
… | …000110001000101010011 |
3 | 102100001012100010002202111 |
4 | 232211132100301011103 |
5 | 404422312003323141 |
6 | 10450401024530151 |
7 | 450200664531016 |
oct | 56453620610523 |
9 | 12301170102674 |
10 | 3201332089171 |
11 | 102474a562217 |
12 | 438533780957 |
13 | 1a2b65b10c08 |
14 | b0d33c8d37d |
15 | 58419ae6381 |
hex | 2e95e431153 |
3201332089171 has 2 divisors, whose sum is σ = 3201332089172. Its totient is φ = 3201332089170.
The previous prime is 3201332089141. The next prime is 3201332089199. The reversal of 3201332089171 is 1719802331023.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3201332089171 is a prime.
It is not a weakly prime, because it can be changed into another prime (3201332089141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600666044585 + 1600666044586.
It is an arithmetic number, because the mean of its divisors is an integer number (1600666044586).
Almost surely, 23201332089171 is an apocalyptic number.
3201332089171 is a deficient number, since it is larger than the sum of its proper divisors (1).
3201332089171 is an equidigital number, since it uses as much as digits as its factorization.
3201332089171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 40.
The spelling of 3201332089171 in words is "three trillion, two hundred one billion, three hundred thirty-two million, eighty-nine thousand, one hundred seventy-one".
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