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320134020125 = 533182615231
BaseRepresentation
bin1001010100010010111…
…10010111110000011101
31010121022200122020001012
410222021132113300131
520221113302121000
6403022331025005
732062135162433
oct4521136276035
91117280566035
10320134020125
1111384a343657
125206429b165
132425b1cba9a
14116cd152d53
1584da09e735
hex4a89797c1d

320134020125 has 16 divisors (see below), whose sum is σ = 412415238144. Its totient is φ = 247845690000.

The previous prime is 320134020113. The next prime is 320134020139. The reversal of 320134020125 is 521020431023.

It is not a de Polignac number, because 320134020125 - 24 = 320134020109 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 320134020125.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41303741 + ... + 41311490.

It is an arithmetic number, because the mean of its divisors is an integer number (25775952384).

Almost surely, 2320134020125 is an apocalyptic number.

It is an amenable number.

320134020125 is a deficient number, since it is larger than the sum of its proper divisors (92281218019).

320134020125 is an equidigital number, since it uses as much as digits as its factorization.

320134020125 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82615277 (or 82615267 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 320134020125 its reverse (521020431023), we get a palindrome (841154451148).

The spelling of 320134020125 in words is "three hundred twenty billion, one hundred thirty-four million, twenty thousand, one hundred twenty-five".

Divisors: 1 5 25 31 125 155 775 3875 82615231 413076155 2065380775 2561072161 10326903875 12805360805 64026804025 320134020125