Base | Representation |
---|---|
bin | 1001010100010011000… |
… | …11101101110100111001 |
3 | 1010121022210021102000101 |
4 | 10222021203231310321 |
5 | 20221114131434431 |
6 | 403022421035401 |
7 | 32062153116346 |
oct | 4521143556471 |
9 | 1117283242011 |
10 | 320135421241 |
11 | 1138501102a9 |
12 | 52064855b61 |
13 | 2425b59c74c |
14 | 116cd3d97cd |
15 | 84da279961 |
hex | 4a898edd39 |
320135421241 has 2 divisors, whose sum is σ = 320135421242. Its totient is φ = 320135421240.
The previous prime is 320135421191. The next prime is 320135421289. The reversal of 320135421241 is 142124531023.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 232979982400 + 87155438841 = 482680^2 + 295221^2 .
It is an emirp because it is prime and its reverse (142124531023) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-320135421241 is a prime.
It is not a weakly prime, because it can be changed into another prime (320135424241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160067710620 + 160067710621.
It is an arithmetic number, because the mean of its divisors is an integer number (160067710621).
Almost surely, 2320135421241 is an apocalyptic number.
It is an amenable number.
320135421241 is a deficient number, since it is larger than the sum of its proper divisors (1).
320135421241 is an equidigital number, since it uses as much as digits as its factorization.
320135421241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 320135421241 its reverse (142124531023), we get a palindrome (462259952264).
The spelling of 320135421241 in words is "three hundred twenty billion, one hundred thirty-five million, four hundred twenty-one thousand, two hundred forty-one".
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