Base | Representation |
---|---|
bin | 1001010100010101001… |
… | …01000010011101100001 |
3 | 1010121100222111101120011 |
4 | 10222022211002131201 |
5 | 20221133022420441 |
6 | 403024232044521 |
7 | 32062451506243 |
oct | 4521245023541 |
9 | 1117328441504 |
10 | 320152545121 |
11 | 113859846772 |
12 | 5206a533741 |
13 | 24261cb6a16 |
14 | 116d17b6093 |
15 | 84dba0d581 |
hex | 4a8a942761 |
320152545121 has 2 divisors, whose sum is σ = 320152545122. Its totient is φ = 320152545120.
The previous prime is 320152545109. The next prime is 320152545149. The reversal of 320152545121 is 121545251023.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 314872488225 + 5280056896 = 561135^2 + 72664^2 .
It is a cyclic number.
It is not a de Polignac number, because 320152545121 - 213 = 320152536929 is a prime.
It is not a weakly prime, because it can be changed into another prime (320152545821) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160076272560 + 160076272561.
It is an arithmetic number, because the mean of its divisors is an integer number (160076272561).
Almost surely, 2320152545121 is an apocalyptic number.
It is an amenable number.
320152545121 is a deficient number, since it is larger than the sum of its proper divisors (1).
320152545121 is an equidigital number, since it uses as much as digits as its factorization.
320152545121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 320152545121 its reverse (121545251023), we get a palindrome (441697796144).
The spelling of 320152545121 in words is "three hundred twenty billion, one hundred fifty-two million, five hundred forty-five thousand, one hundred twenty-one".
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