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320404415120513 is a prime number
BaseRepresentation
bin100100011011001111111011…
…1010110010000010010000001
31120000110100210120210211020122
41020312133313112100102001
5313444001220232324023
63053235431205550025
7124326312044355323
oct11066376726202201
91500410716724218
10320404415120513
11930aa827456289
122bb28632415315
13109a2011952319
145919929389613
1527096c2a122c8
hex12367f7590481

320404415120513 has 2 divisors, whose sum is σ = 320404415120514. Its totient is φ = 320404415120512.

The previous prime is 320404415120333. The next prime is 320404415120527. The reversal of 320404415120513 is 315021514404023.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 215310076208704 + 105094338911809 = 14673448^2 + 10251553^2 .

It is a cyclic number.

It is not a de Polignac number, because 320404415120513 - 212 = 320404415116417 is a prime.

It is not a weakly prime, because it can be changed into another prime (320404415180513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160202207560256 + 160202207560257.

It is an arithmetic number, because the mean of its divisors is an integer number (160202207560257).

Almost surely, 2320404415120513 is an apocalyptic number.

It is an amenable number.

320404415120513 is a deficient number, since it is larger than the sum of its proper divisors (1).

320404415120513 is an equidigital number, since it uses as much as digits as its factorization.

320404415120513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 320404415120513 its reverse (315021514404023), we get a palindrome (635425929524536).

The spelling of 320404415120513 in words is "three hundred twenty trillion, four hundred four billion, four hundred fifteen million, one hundred twenty thousand, five hundred thirteen".