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320544443443963 is a prime number
BaseRepresentation
bin100100011100010001001000…
…1101011111010101011111011
31120000221202020101210200110111
41020320202101223322223323
5314003300010010201323
63053424030122525151
7124342400061441304
oct11070422153725373
91500852211720414
10320544443443963
1193154153825232
122bb4b7b16667b7
13109b229935014b
14592261066b7ab
15270d16ae7ac0d
hex1238891afaafb

320544443443963 has 2 divisors, whose sum is σ = 320544443443964. Its totient is φ = 320544443443962.

The previous prime is 320544443443943. The next prime is 320544443443999. The reversal of 320544443443963 is 369344344445023.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-320544443443963 is a prime.

It is a super-2 number, since 2×3205444434439632 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 320544443443898 and 320544443443907.

It is not a weakly prime, because it can be changed into another prime (320544443443933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160272221721981 + 160272221721982.

It is an arithmetic number, because the mean of its divisors is an integer number (160272221721982).

Almost surely, 2320544443443963 is an apocalyptic number.

320544443443963 is a deficient number, since it is larger than the sum of its proper divisors (1).

320544443443963 is an equidigital number, since it uses as much as digits as its factorization.

320544443443963 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 179159040, while the sum is 58.

Adding to 320544443443963 its reverse (369344344445023), we get a palindrome (689888787888986).

The spelling of 320544443443963 in words is "three hundred twenty trillion, five hundred forty-four billion, four hundred forty-three million, four hundred forty-three thousand, nine hundred sixty-three".