Base | Representation |
---|---|
bin | 101110101101101110110… |
… | …101001111010010011011 |
3 | 102100220002100200200002121 |
4 | 232231232311033102123 |
5 | 410043442201120443 |
6 | 10454425011242111 |
7 | 450633514643065 |
oct | 56555665172233 |
9 | 12326070620077 |
10 | 3210200020123 |
11 | 1028490248a78 |
12 | 43a1a95a9337 |
13 | 1a394a0cca35 |
14 | b1535926735 |
15 | 587883d64ed |
hex | 2eb6ed4f49b |
3210200020123 has 2 divisors, whose sum is σ = 3210200020124. Its totient is φ = 3210200020122.
The previous prime is 3210200020051. The next prime is 3210200020141.
3210200020123 is nontrivially palindromic in base 10.
It is a strong prime.
It is a palprime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3210200020123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3210200020097 and 3210200020106.
It is not a weakly prime, because it can be changed into another prime (3210200020163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1605100010061 + 1605100010062.
It is an arithmetic number, because the mean of its divisors is an integer number (1605100010062).
Almost surely, 23210200020123 is an apocalyptic number.
3210200020123 is a deficient number, since it is larger than the sum of its proper divisors (1).
3210200020123 is an equidigital number, since it uses as much as digits as its factorization.
3210200020123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 16.
It can be divided in two parts, 32102000 and 20123, that added together give a palindrome (32122123).
The spelling of 3210200020123 in words is "three trillion, two hundred ten billion, two hundred million, twenty thousand, one hundred twenty-three".
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