Base | Representation |
---|---|
bin | 1110100110010101010001… |
… | …11100100111010000001101 |
3 | 11012200001112112120120122020 |
4 | 13103022220330213100031 |
5 | 13201440301012011023 |
6 | 152140035122240353 |
7 | 6522252450561501 |
oct | 723125074472015 |
9 | 135601475516566 |
10 | 32103420032013 |
11 | a257a90745680 |
12 | 3725a364b60b9 |
13 | 14bb454c00a25 |
14 | 7cdb571a0301 |
15 | 3aa13c3a3de3 |
hex | 1d32a8f2740d |
32103420032013 has 8 divisors (see below), whose sum is σ = 46695883682976. Its totient is φ = 19456618201200.
The previous prime is 32103420032009. The next prime is 32103420032059. The reversal of 32103420032013 is 31023002430123.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 32103420032013 - 22 = 32103420032009 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32103400032013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 486415454998 + ... + 486415455063.
It is an arithmetic number, because the mean of its divisors is an integer number (5836985460372).
Almost surely, 232103420032013 is an apocalyptic number.
32103420032013 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
32103420032013 is a deficient number, since it is larger than the sum of its proper divisors (14592463650963).
32103420032013 is a wasteful number, since it uses less digits than its factorization.
32103420032013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 972830910075.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 32103420032013 its reverse (31023002430123), we get a palindrome (63126422462136).
The spelling of 32103420032013 in words is "thirty-two trillion, one hundred three billion, four hundred twenty million, thirty-two thousand, thirteen".
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