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32104043133 = 310701347711
BaseRepresentation
bin11101111001100011…
…001101001001111101
310001212101102100221120
4131321203031021331
51011222113340013
622425353021153
72214365602251
oct357143151175
9101771370846
1032104043133
1112684993858
12627b6b47b9
13304826a336
1417a7a68261
15c7d6de123
hex7798cd27d

32104043133 has 4 divisors (see below), whose sum is σ = 42805390848. Its totient is φ = 21402695420.

The previous prime is 32104043123. The next prime is 32104043189. The reversal of 32104043133 is 33134040123.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 32104043133 - 210 = 32104042109 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32104043123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5350673853 + ... + 5350673858.

It is an arithmetic number, because the mean of its divisors is an integer number (10701347712).

Almost surely, 232104043133 is an apocalyptic number.

It is an amenable number.

32104043133 is a deficient number, since it is larger than the sum of its proper divisors (10701347715).

32104043133 is a wasteful number, since it uses less digits than its factorization.

32104043133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10701347714.

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 32104043133 its reverse (33134040123), we get a palindrome (65238083256).

The spelling of 32104043133 in words is "thirty-two billion, one hundred four million, forty-three thousand, one hundred thirty-three".

Divisors: 1 3 10701347711 32104043133