321043320340130 has 8 divisors (see below), whose sum is σ = 577877976612252. Its totient is φ = 128417328136048.

The previous prime is 321043320340103. The next prime is 321043320340139. The reversal of 321043320340130 is 31043023340123.

It can be written as a sum of positive squares in 2 ways, for example, as 298783428334609 + 22259892005521 = 17285353^2 + 4718039^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×321043320340130³ (a number of 44 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 321043320340093 and 321043320340102.

It is not an unprimeable number, because it can be changed into a prime (321043320340139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16052166016997 + ... + 16052166017016.

Almost surely, 2^{321043320340130} is an apocalyptic number.

321043320340130 is a deficient number, since it is larger than the sum of its proper divisors (256834656272122).

321043320340130 is a wasteful number, since it uses less digits than its factorization.

321043320340130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32104332034020.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 321043320340130 its reverse (31043023340123), we get a palindrome (352086343680253).

The spelling of 321043320340130 in words is "three hundred twenty-one trillion, forty-three billion, three hundred twenty million, three hundred forty thousand, one hundred thirty".