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32105421140131 is a prime number
BaseRepresentation
bin1110100110011001000000…
…01110001111000010100011
311012200020201000000101220201
413103030200032033002203
513202003400302441011
6152141005445050031
76522353156660113
oct723144016170243
9135606630011821
1032105421140131
11a258918279839
1237262b46b6917
1314bb6b3675581
147cdca6c67043
153aa207dd4cc1
hex1d332038f0a3

32105421140131 has 2 divisors, whose sum is σ = 32105421140132. Its totient is φ = 32105421140130.

The previous prime is 32105421140083. The next prime is 32105421140281. The reversal of 32105421140131 is 13104112450123.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 32105421140131 - 231 = 32103273656483 is a prime.

It is a super-2 number, since 2×321054211401312 (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 32105421140131.

It is not a weakly prime, because it can be changed into another prime (32105421170131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16052710570065 + 16052710570066.

It is an arithmetic number, because the mean of its divisors is an integer number (16052710570066).

Almost surely, 232105421140131 is an apocalyptic number.

32105421140131 is a deficient number, since it is larger than the sum of its proper divisors (1).

32105421140131 is an equidigital number, since it uses as much as digits as its factorization.

32105421140131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 32105421140131 its reverse (13104112450123), we get a palindrome (45209533590254).

The spelling of 32105421140131 in words is "thirty-two trillion, one hundred five billion, four hundred twenty-one million, one hundred forty thousand, one hundred thirty-one".